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The slope of a line perpendicular to the line which passes through the points (–k, h) and (b, – f ) is(a) –1 (b) \(\frac{f-h}{b+k}\)(c) \(\frac{b+k}{f+h}\)(d) \(\frac{-b+k}{f-h}\) |
Answer» (c) \(\frac{b+k}{f+h}\) Let the slope of the lin passing through the points (–k, h) and (b, – f) be m1. Then m1 = \(\frac{-f-h}{b+k}\) = \(-\bigg(\frac{f+h}{b+k}\bigg)\) \(\bigg[Slope = \frac{y_2-y_1}{x_2-x_1}\bigg]\) ∴ Slope of line perpendicular to the given line = \(-\frac{1}{m_1}\) = \(\frac{-1}{-\big(\frac{f+h}{b+k}\big)}\) = \(\bigg(\frac{b+k}{f+h}\bigg)\) |
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