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The smallest number which when diminished by 3 is divisible by 14, 28, 36 and 45, is? |
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Answer» Answer: 1263 Solution - Here, at FIRST we have to find the prime factorisation of the GIVEN numbers Prime Factors of 14 = 2 × 7 Prime Factors of 28 = 2 × 2 × 7 Prime Factors of 36 = 2 × 2 × 3 × 3 Prime Factors of 45 = 3 × 3 × 5 ∴ LCM of 14, 28, 36 & 45 = 2 × 2 × 3 × 3 × 5 × 7 = 1260 ∴ REQUIRED smallest number = 1260 + 3 = 1263 The required smallest number is 1263 |
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