1.

The smallest number which when diminished by 3 is divisible by 14, 28, 36 and 45, is?​

Answer»

Answer: 1263

Solution -

Here, at FIRST we have to find the prime factorisation of the GIVEN numbers

Prime Factors of 14 = 2 × 7

Prime Factors of 28 = 2 × 2 × 7

Prime Factors of 36 = 2 × 2 × 3 × 3

Prime Factors of 45 = 3 × 3 × 5

∴ LCM of 14, 28, 36 & 45

= 2 × 2 × 3 × 3 × 5 × 7

= 1260

REQUIRED smallest number = 1260 + 3

= 1263

The required smallest number is 1263



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