1.

The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is1). 10152). 10083). 10224). 1032

Answer»

If the number is DIVISIBLE by 12, 16, 18, 21 and 28, then it should be divisible by the LCM of 12, 16, 18, 21 and 28.

In this case we will evaluate the LCM of 12, 16, 18, 21 and 28 which is 1008.

But it is given that the number is only divisible by 12, 16, 18, 21 and 28 after we subtract 7 from it.

∴ The number needs to 1008 + 7 = 1015


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