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The smallest of three consecutive integers is added to four times the largest integer, the result so obtained is 15 less than three times the middle number. Find the integers​

Answer»

Answer LET the three integers be x, x+2 and x+4 Now from the given information, the equation we get is x+4(x+4)=4(x+2)+729 ⇒x+4x+16=4x+8+729 ⇒5x−4x=737−16 ⇒x=721 So the three CONSECUTIVE odd integers are, x=721 x+2=723, and x+4=725 Therefore, the NUMBERS are 721,723,725. Step-by-step explanation:Answer Let the three integers be x, x+2 and x+4 Now from the given information, the equation we get is x+4(x+4)=4(x+2)+729 ⇒x+4x+16=4x+8+729 ⇒5x−4x=737−16 ⇒x=721 So the three consecutive odd integers are, x=721 x+2=723, and x+4=725 Therefore, the numbers are 721,723,725.


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