1.

The solubility of Sb_(2)S_(3) in water is 1.0 xx 10^(-5) mole/litre at 298 K. What will be its solubility product

Answer»

`108 xx 10^(-25)`
`1.0 xx 10^(-25)`
`144 xx 10^(-25)`
`126 xx 10^(-24)`

Solution :`{:(Sb_(2) rarr,2Sb^(+2)+,3S^(-),,K_(sp) = (2x)^(2).(3x)^(3),),(,2x,3x,,):}`
`K_(sp) = 108x^(5), K_(sp) = 108 xx (1 xx 10^(-5))^(5) = 108 xx 10^(-25)`.


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