1.

The solubility product constant K_(sp) of Mg(OH)_(2) is 9.0 xx 10^(-12). If a solution is 0.010 M with respect to Mg^(2+) ion, what is the maximum hydroxide ion concentration which could be present without causing the precipitation of Mg(OH)_(2)

Answer»

`1.5 xx 10^(-7) M`
`3.0 xx 10^(-7) M`
`1.5 xx 10^(-5) M`
`3.0 xx 10^(-5) M`

Solution :`{:("MG"(OH)_(2),hArr,Mg^(++)+,2OH^(-)),(K_(sp),=,S,(2S)^(2)):}`
`K_(sp) = S xx 4S^(2)`
`(K_(sp))/(S xx 4) = S^(2) = (9 xx 10^(-12))/(0.010 xx 4) = 2.25 xx 10^(-10)`
`S = sqrt(2.25 xx 10^(-10)) = 1.5 xx 10^(-5) m/l`
`= 1.5 xx 2 xx 10^(-5) m//l = 3 xx 10^(-5)m//l`.


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