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The solutio of the differential equation `(x^(2)-xy^(2))(dy)/(dx)+y^(2)+xy^(2) = 0` isA. `log((x)/(y))=(1)/(x)+(1)/(y)+c`B. `log((y)/(x))=(1)/(x)+(1)/(y)+c`C. `log(xy) = (1)/(x) + (1)/(y)+c`D. `log(xy)+(1)/(x)+(1)/(y)=c` |
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Answer» Correct Answer - A The given equation `(x^(2)-yx^(2))(dy)/(dx)+ y^(2)+xy^(2)=0` `rArr" "(1-y)/(y^(2))dy+(1+x)/(x^(2))dx = 0` `rArr" "((1)/(y^(2))-(1)/(y))dy+((1)/(x^(2))+(1)/(x))dx = 0` On integrating, we get the required solution `log((x)/(y))=(1)/(x)+(1)/(y)+c` |
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