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The solution at x=1,t=1 of the partial differential equation ∂2u∂x2=25∂2u∂t2 subject to initial conditions of u(0)=3x and ∂u∂t(0)=3 is |
Answer» The solution at x=1,t=1 of the partial differential equation ∂2u∂x2=25∂2u∂t2 subject to initial conditions of u(0)=3x and ∂u∂t(0)=3 is |
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