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The solution of the differential equation`(dy)/(dx)=1/(x y[x^2siny^2+1])`is(a) `( b ) (c) (d) x^(( e )2( f ))( g )(cos( h ) y^(( i )2( j ))( k )-sin( l ) y^(( m )2( n ))( o )-2C (p) e^( q ) (r)-( s ) y^((( t )2( u ))( v ) (w))( x ))=2( y )`(z)(aa)`( b b ) (cc) (dd) y^(( e e )2( f f ))( g g )(cos( h h ) y^(( i i )2( j j ))( k k )-sin( l l ) y^(( m m )2( n n ))( o o )-2C (pp) e^( q q ) (rr)-( s s ) y^((( t t )2( u u ))( v v ) (ww))( x x ))=2( y y )`(zz)(aaa)`( b b b ) (ccc) (ddd) x^(( e e e )2( f f f ))( g g g )(cos( h h h ) y^(( i i i )2( j j j ))( k k k )-sin( l l l ) y^(( m m m )2( n n n ))( o o o )-( p p p ) e^( q q q ) (rrr)-( s s s ) y^((( t t t )2( u u u ))( v v v ) (www))( x x x ))=4C (yyy)`(zzz)(aaaa)None of these |
Answer» `- (1)/(x^(2)) = (1)/(2)(sin y^(2) - cos y^(2)) + ke^(-y^(2))` | |