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The solution of the differential equation `sinxcosy dy + cosx siny dx= 0` isA. `(sinx)/(siny)=C`B. `cosx+cosy=C`C. `sinx+siny=C`D. `sinxsiny=C` |
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Answer» Correct Answer - D We have, `cosx sinydx +sinx cosy dy =0` `rArr" "sinyd(sinx)+sinxd(siny)=0` `rArr" "d(sin x siny)=0` On integrating, we get `sin x sin y =C`. |
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