1.

The solution of the differential equation `sinxcosy dy + cosx siny dx= 0` isA. `(sinx)/(siny)=C`B. `cosx+cosy=C`C. `sinx+siny=C`D. `sinxsiny=C`

Answer» Correct Answer - D
We have,
`cosx sinydx +sinx cosy dy =0`
`rArr" "sinyd(sinx)+sinxd(siny)=0`
`rArr" "d(sin x siny)=0`
On integrating, we get `sin x sin y =C`.


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