InterviewSolution
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InterviewSolution
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The solution of the differential equation `(x^2y^2-1)dy+2xy^3dx=0`is(a)`( b ) (c)1+( d ) x^(( e )2( f ))( g ) (h) y^(( i )2( j ))( k )=c x (l)`(m) (b) `( n ) (o)1+( p ) x^(( q )2( r ))( s ) (t) y^(( u )2( v ))( w )=c y (x)`(y)(c)`( d ) (e) y=0( f )`(g)(d) `( h ) (i) y=-( j )1/( k )(( l ) (m) x^(( n )2( o ))( p ))( q ) (r) (s)`(t)A. `1+x^(2)y^(2)=cx`B. `1+x^(2)y^(2)=cy`C. `y=0`D. `y=-1/x^(2)` |
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Answer» Correct Answer - B `(x^(2)y^(2)-1)dy+2xy^(3)dx=0` or `x^(2)y^(2)dy+2xy^(3)dx=dy` or `x^(2)dy+2xydx=(dy)/y^(2)` or `intd(x^(2)y)=int(dy)/(y^(2))+c` or `x^(2)y=y^(-1)/-1+c` or `x^(2)y^(2)=-1+cy` i.e., `1+x^(2)y^(2)=cy` |
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