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The solution of the differential equation `(x+y)(dx-dy)=dx+dy`, isA. `x-y=ke^(x-y)`B. `x+y=ke^(x+y)`C. `x+y=k(x-y)`D. `x+y=ke^(x-y)` |
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Answer» Correct Answer - D We have, `(x+y)(dx-dy)=dx+dy` `rArr" "dx-dy=(dx+dy)/(x+y)` `rArr" "d(x-y)=(d(x+y))/(x+y)` `rArr" "x-y=log(x+y)+logC" [On integrating]"` `rArr" "c(x+y)=e^(x-y)` `rArr" "x+y=ke^(x-y)," where k"=(1)/(C)` |
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