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The solution of the equation4 cos2x+6 si?x=5x=nnx=nnx=nn:none of these |
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Answer» Consider given the TRIGONOMETRY equation,4cos 2 X+6sin 2 x=54(1−sin 2 x)+6sin 2 x=52sin 2 x+4=52sin 2 x=1sin 2 x= 21 sinx= 2 1 orsinx=− 2 1 sinx=sin 4π orsinx=sin(− 4π )x= 4π orx=− 4π x=nπ+(−1) n 4π orx=nπ−(−1) n 4π HENCE, this is the ANSWER. |
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