1.

The specific heat capacity of a metal at low temperature (T) is given as : C_(p) (kJK^(-1)kg^(-1))=32 ((T)/(400))^(3) A 100 gram vessel of this metal is to be cooled from 20K to 4K by a special refrigerator operating at room temperature (27^(@)C). The amount of work required to cool the vessel is:

Answer»

greater than 0.148 k
between 0.148 KJ and 0.028 k
less than 0.028 kJ
equal to 0.002 kJ

Solution :`Q= int" mod "T= overset(4)UNDERSET(20)int 0.1xx32xx((T_(3))/(400^(3)))DT ~~ 0.002 kJ.`
Correct choice : (d).


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