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The specific heat of a gas is found to be0.075 calories at constant volume and its formulawt is 40. The atomicity of the gas would be(1) One(2) Two(3) Three(4) Four |
Answer» Specificheat of gas at constant volume=0.075calg^-1C° i.e,0.075cal is absorbed by 1g of it for 1° rise in temperature at constant volume. So,total heat absorbed by 1g mole of the gas is 40(0.075)=3cal. Since,Cp-Cv=R or Cp=5 Cp/Cv=5/3 & hence the gas is monatomic. |
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