1.

The specific heat of a gas is found to be0.075 calories at constant volume and its formulawt is 40. The atomicity of the gas would be(1) One(2) Two(3) Three(4) Four

Answer»

Specificheat of gas at constant volume=0.075calg^-1C°

i.e,0.075cal is absorbed by 1g of it for 1° rise in temperature at constant volume.

So,total heat absorbed by 1g mole of the gas is 40(0.075)=3cal.

Since,Cp-Cv=R or Cp=5 Cp/Cv=5/3 & hence the gas is monatomic.



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