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The specific resistance of the material of a sonducting wire is rho and current through cross sectional area of the wire (I,e., current decsity ) is J . What is the power cousumed per unit volume of the wire ? |
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Answer» Solution :Let length of the wire = l , cross sectianal area of the wire = A and current through the wire = I . So , resistance , `R=rho.(l)/(A),"currentdensity ", J = (I)/(A),`VOLUME of the wire = IA Power consumed , `P=I^(2)R` So , power consumed per unit volume , `(P)/(lA)=(I^(2)R)/(lA)=(l^(2))/(lA).rho(l)/(A)=((I)/(A))^(2).rho=J^(2)rho` |
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