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The speed of a car weighing 3000N increases from 36 km/h to 72km/h uniformly. the change in momentum of the car is 3×10power x find x pls don't spam.... |
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Answer» -Given:Weight of car (W) = 3000 NWE know that,W = mgwhere,m is massg is acceleration DUE to gravity.g on the EARTH is 9.8 m/s² ≈ 10 m/s².So, m * 10 = 3000⟶ m = 300 kgInitial Velocity (u) = 36 km/h 1 km/h = 5/18 m/s.⟹ u = 36 * 5/18 = 10 m/sFinal velocity (v) = 72 km/h⟹ v = 72 * 5/18 = 20 m/sNow,Change in MOMENTUM (∆ P) = Final momentum (P_f) - Initial momentum(Pᵢ)We know that,P = mass * velocity⟶ ∆ P = mv - mu⟶ ∆ P = (300)(20) - 300(10)⟶ ∆ P = 6000 - 3000⟶ ∆ P = 3000 kg.m/s⟶ ∆ P = 3 × 10³ kg.m/s∴ The value of X is 3. |
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