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The speed of a certain monochromatic light, in a given transparent medium, is 2.25xx10^(8)ms^(-1). What is the (a) critical angle of incidence, (b) polarising angle for this medium ? |
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Answer» Solution :(a) As per QUESTION speed of light in given medium `V=2.25xx10^(8)ms^(-1)` and we know that the speed of light in free space `c=3xx10^(8)ms^(-1)` `therefore `Refractive index of medium `n=(c)/(v)=(3xx10^(8))/(2.25xx10^(8))=(4)/(3)` `therefore` CRITICAL angle `i_(c)=SIN^(-1)((1)/(n))=sin^(-1)((3)/(4))=48.6^(@)` (b) The polarising angle `i_(p)=tan^(-1)(n)=tan^(-1)((4)/(3))=53.1^(@)`. |
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