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The speed of a homogeneous solid sphere after rolling down an inclined plane of vertical height `h` from rest without slipping will be.A. `sqrt((10 gh)/(7))`B. `sqrt((6gh)/(5))`C. `sqrt((4 gh)/(5))`D. `sqrt(2gh)` |
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Answer» Correct Answer - B In pure rolling, mechanical energy remains conserved. Therefore, at bottomost post, total kinetic energy will be `mgh` Ratio of rotational to translational kinetic energy will be `(2)/(3)` `:. K_(T)=(3)/(5)(mgh)rArr(3)/(5)mgh=(1)/(2)mv^(2)` `:.` The speed of a uniform spherical shell `v=sqrt((6gh)/(5))`. |
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