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The speed of an electron in first Bohr orbit is (c )/(137), where c is the velocity of light in vacuum, then the speed of electron in second orbit is ………….. |
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Answer» `(1)/(2)((C)/(137))` `mvr_(n)=(nh)/(2PI)` `:V=(nh)/(2pimr_(n))` but `r_(n)LTN^(2)` `:.r_(n)=Kn^(2)` (K constant) `:.v=(nh)/(2pimKn^(2))` `:.vprop(1)/(n)` (All others terms are constant) `:.(v_(2))/(v_(1))=(n_(1))/(n_(2))` `:.(v_(2))/(v_(1))=(1)/(2)` `:.v_(2)=(v_(1))/(2)` `:.v_(2)=(1)/(2)((c)/(137))` |
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