Saved Bookmarks
| 1. |
The speed of water is double that of swimmer's velocity relative to water ?What should be the direction of the swimmer so as to express minimum displacement assuming v_m= 5m//sec ? |
|
Answer» SOLUTION :Putting the value of `(V_(mw))/(V_(W))=(1)/(2)` in the derived expression `THETA`= `sin^(-1)(V_(mw))/(V_(w))` we obatin `theta=sin^(-1)((1)/(2))=30^(@)implies 120^(@)` from direction of river flow |
|