1.

The speed withwhicha bullentcan be firedis 150 ms^(-1). Calculate the greatest distanceto whichit canbe projectedandalsothe maximum height to whichit would rise .

Answer»

Solution :`R=(U^(2) sin 2alpha)/G =((150^(2) sin 90^(@))/9.8) = 2295.1` m
`H_("max") =(u^(2)sin^(2)alpha)/(2g) =((150)^(2) sin^(2)45^(@))/(2 xx 9.8) = 573.97` m


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