1.

The spherical shell has radius r. The potential difference V is between centre to distnnce 3r. The electric field at a distance 3r will be ........

Answer»

`(V)/(6r)`
`(V)/(4r)`
`(V)/(3r)`
`(V)/(2R)`

Solution :The potential at the centre of spherical shell`V_(1)=(kq)/(R)` and potential `V_(2)` between centre to distance `2r = V_(2) =(kq)/(3r)`
`:. V= V_(1)-V_(2)`
`= kq [(1)/(r) -(1)/(3r)]`
`= kq[(2)/(3r)]`
`:. (3Vr)/(2) = kq`

Now `E= (kq)/((3r)^(2))=(3Vr)/(2)xx(1)/(9R^(2))=(V)/(6r)`


Discussion

No Comment Found

Related InterviewSolutions