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The spring as shown in figure is kept in a stretched position with extension `x` when the system is relesed. Assuming the horizontal surface to be frictionless, the frequency of oscillation is A. `(1)/(2pi) sqrt([(k(M + m))/(Mm)])`B. `(1)/(2pi) sqrt([(mM)/(k(M + m))])`C. `(1)/(2pi) sqrt([(kM)/(m + M)])`D. `(1)/(2pi) sqrt ([(km)/(M + m)])` |
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Answer» Correct Answer - A `f = (1)/(2pi) sqrt((k)/(mu))` Where, `mu` = reduced mass ` = (M m)/(M + m)`. |
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