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The spring constants of two springs of same length are `k_(1)` and `k_(2)` as shown in figure. If an object of mass m is suspended and set in vibration , the period will be A. `2pisqrt((mk_(1))/(k_(2)))`B. `2pisqrt((m)/(k_(1)k_(2)))`C. `2pisqrt((m)/(k_(1)-k_(2)))`D. `2pisqrt(m//(k_(1)+k_(2)))` |
Answer» Correct Answer - D (d) The springs are corrected in parallel. So, the efffective force constant will be `k_(e)=k_(1)+k_(2)` `therefore T=2pisqrt((m)/(k_(e)))=2pisqrt((m)/(k_(1)+k_(2))` |
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