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The standard electrode potential for the following reaction is `+1.33V`. What is the potential at `pH =2.0 ?` `Cr_(2)O_(7)^(2-)(aq,1M)+14H^(+)(aq)+6e^(-) rarr 2Cr^(3+)(aq. 1M)+7H_(2)O(l)`A. `+1.820V`B. `+1.990V`C. `+1.608V`D. `+1.0542V` |
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Answer» Correct Answer - 4 `E_(Cr_(2)O_(7)^(2-)|Cr^(3+))=E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)-(0.0591)/(6)xx(log.([Cr^(3+)]^(2))/([Cr_(2)O_(7)^(2-)])xx(1)/([H^(+)]^(14)))` `E_(Cr_(2)O_(7)^(2+)|Cr^(3+))=1.33-(0.0591)/(6)log.(1)/((0.01)^(14))" "rArr" "1.0542V` |
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