1.

The standard emf of a galvanic cell involving cell reaction with n=2 found to be 0.295 V at 25^(@)C. The equilibrium constant of the reaction would be

Answer»

`2xx10^(11)`
`4xx10^(12)`
`1xx10^(2)`
`1xx10^(10)`

Solution :`E_(cell)^(o)=(2.303RT)/(nF)log" "K_(EQ)`
`0.295=(2.303xx8.314xx298)/(2xx96500)log" "K_(eq)`
`log" "K_(eq)=(2xx96500)/(2.303xx3.314xx298)=10`
`K_(eq)="antilog "10=1xx10^(10)`


Discussion

No Comment Found

Related InterviewSolutions