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The standard enthalpy of formation of ammonia gas is Given: `N_(2)H_(4) (g) + H_(2) (g) rarr 2NH_(3) (g), Delta H_(r)^(@) = - 40 kJ//mol` `DeltaH_(f)^(@) [N_(2)H_(4) (g)] = - 120 kJ//mol`A. `-60`B. `-180`C. 40D. `-80` |
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Answer» Correct Answer - D `Delta_(r)H^(@)= sum_(i) a_(i) Delta_(f) H_("(products)")^(@)-sum_(i) b_(i) Delta_(f) H_("(reactants)")^(@)` `-40=2Delta_(f) H^(@)+120` `Delta_(f)H^(@)=-80` |
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