1.

The standard Gibbs energy change at 300K for the reaction 2A⇋B+C is 2494.2 J. At a given time, the composition of the reaction mixture is [A] =21​ , [B] = 2 and [C] =21​ . The reaction proceeds in the : [R=8.314J/K/mol,e=2.718]

Answer»

FORWARD direction because Q>K_c`
reverse direction because Q>`K_c`
forward direction because Qreverse direction because Q

Solution :`2A0=294.2J`
R`=8.314.K^(-1).mol^(-1)" "/_\G^(0)=2.303RTlogK_c`
or `294.2=-2.303xx8.314xx300xxlogK_c`
or `K_c`=ANTILOG`(-04342)" or "K_c=0.3679`
`Q=([B][C])/([A]^2)=(2xx1/2)/((1/2)^2)=4`
Here, `Q>K_c`. Thus, the reaction will PROCEED in the backward direction.


Discussion

No Comment Found

Related InterviewSolutions