1.

The standard Gibbs free energy change DeltaG^(@) is related to equilibrium constant K_(p) as

Answer»

<P>`K_(p)=-RTlnDeltaG^(@)`
`K_(p)=((E)/(RT))^(DeltaG^(@))`
`K_(p)=-(DeltaG^(@))/(RT)`
`K_(p)=e^(-(DeltaG^(@))/(RT))`

Solution :`K_(p)=e^(-DeltaG^(@)//RT)`


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