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The standard heat of formation of `U_(3)O_(8)` is -853.5 kcl//mol and the standard heat of the reaction `3UO_(2) +O_(2) rarr U_(3)O_(8)` is -76.01 Kcal. The standard heat of formation of `UO_(2)` isA. `-1083KJmol^(-1)`B. `-108.3KJmol^(-1)`C. `-10.83KJmol^(-1)`D. `-1.083KJmol^(-1)` |
Answer» Correct Answer - C `3U O_(2) + O_(2) rarr U_(3)O_(8)` `Delta H^(@) = Delta H_(f)^(@) (U_(3)O_(8)) - Delta H_(f)^(@) (O_(2)) - 3 Delta H_(f)^(@) (U O_(2))` `implies 3DeltaH_(f)^(@) (UO_(2))=-DeltaH^(@) + DeltaH_(f)^(@)(U_(3)O_(8)) - DeltaH_(f)^(@)(O_(2))` or `Delta H_(f)^(@) (UO_(2)) = (-(-76.0) + (-583.5)-0)/(3)` `=-259.17` Kcal `=-1083.33` KJ/mol |
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