The standard heats of formation of `CH_(4)(g), CO_(2)(g)` and `H_(2)O(g)` are `-76.0, -390.0`, and `-240.0 kJ mol^(-1)`, respectively. Calculate the amount of heat evolved by burning `1m^(3)` of methane measured under normal conditions.

The standard heats of formation of `CH_(4)(g), CO_(2)(g)` and `H_(2)O(

1.	The standard heats of formation of `CH_(4)(g), CO_(2)(g)` and `H_(2)O(g)` are `-76.0, -390.0`, and `-240.0 kJ mol^(-1)`, respectively. Calculate the amount of heat evolved by burning `1m^(3)` of methane measured under normal conditions.
Answer» The required for the conustion of mathane is: `CH_(4) +2O_(2)rarr CO_(2)+2H_(2)O,DeltaH=?` `DeltaH^(Theta) = Delta_(f)H^(Theta)("product")-Delta_(f)H^(Theta)("reactants")` `=Delta_(f)H_((CO_(2)))^(Theta)+2xxDelta_(f)H^(Theta)H_((H_(2)O))^(Theta)-Delta_(f)H_((CH_(4)))^(Theta)-2Delta_(f)H_((O_(2)))^(Theta)` `=- 390.0 - 2 xx 240.0 -(-76.0) - 2xx0` `=- 718.0 kJ mol^(-1)`. Heat evolved by buring `22.4L` (1mol) methane `= 718.0 kJ`. So, heat evolved by buring `1000L (1m^(3))` methane `=-(718.0)/(22.4) xx 1000 =- 32053.5 kJ`

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The standard heats of formation of `CH_(4)(g), CO_(2)(g)` and `H_(2)O(g)` are `-76.0, -390.0`, and `-240.0 kJ mol^(-1)`, respectively. Calculate the amount of heat evolved by burning `1m^(3)` of methane measured under normal conditions.

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