The standard state Gibba free energies of formations of C("graphite") and ("diamond") at T =298k are DeltafG^(@) [ C("graphite") = " O "kJ mol^(-1) DeltafG^(@) [ C("graphite") = " O "kJ mol6^(-1) The standed state means that the presses should be 1 bar, and substance of graphite [C(graphite)] to diamond [C(diamond )] reduces its volumeby 2xx 10^(10) m^(-1)If C(graphite) is converted to C(diamond ) isothemally at T= 298k the pressure at which C( graphite) is in equilibrium with C(diamond) ,is [ useful infromation : 1 J - Kgm^(2) s^(-2)1pa = 1kg m^(-1)s^(-2) : 1^(-) = 10 ^(5) pa]

The standard state Gibba free energies of formations of C("graphite")

1.	The standard state Gibba free energies of formations of C("graphite") and ("diamond") at T =298k are DeltafG^(@) [ C("graphite") = " O "kJ mol^(-1) DeltafG^(@) [ C("graphite") = " O "kJ mol6^(-1) The standed state means that the presses should be 1 bar, and substance of graphite [C(graphite)] to diamond [C(diamond )] reduces its volumeby 2xx 10^(10) m^(-1)If C(graphite) is converted to C(diamond ) isothemally at T= 298k the pressure at which C( graphite) is in equilibrium with C(diamond) ,is [ useful infromation : 1 J - Kgm^(2) s^(-2)1pa = 1kg m^(-1)s^(-2) : 1^(-) = 10 ^(5) pa]
Answer» 58001 BAR 1450 bar 14501 bar 29001 Answer :C