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The steam temperature in a boiler is 600^@C, the pressure is 200 atm. The steam is ejected from a Laval nozzle. Find the velocity and the temperature of steam in the critical cross section. To avoid the condonsation of steam as it leaves the nozzle, its temperature should exceed 100^@C. What is the maximum speed at which the steam leaves the nozzle? |
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Answer» `(a_0^2)/(gamma - 1) = (v_(cr)^2)/(2) + (v_(cr)^2)/(gamma - 1) `, where `v_(cr) = a_0 sqrt(2/(gamma + 1))` To find the velocity of steam LEAVING the nozzle, we make use of the Barnoulli EQUATION in the form of (30.8) and obtain `v = sqrt(2c_p (T_0 - T))`. |
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