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The straight lines represented by the equation `135 x^2-136 x y+33 y^2=0`are equally inclined to the line`x-2y=7`(b) x+2y=7`x-2y=4`(d) `3x+2y=4`A. `x-2y=7`B. `x+2y=7`C. `x-2y=4`D. `3x+2y=4` |
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Answer» Correct Answer - 2 The given pair of lines is `135x^(2)-136xy+33y^(2)=0` (1) the equation of bisectors of angles between the pairs of lines (1) is `(x^(2)-y^(2))/(a-b)=(xy)/(h)or(x^(2)-y^(2))/(135-33)=(xy)/(-68)` or `2x^(2)+3xy-2y^(2)=0`(2) or `(x+2)(2x-y)=0` One of the bisectors is `x+2y=0` which is parallel to the line `x+2y=7`. Hence , the line `x+2y=7` is equally inclined to the given lines. |
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