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The strength of the magnetic field in a long solenoid having 5000 turns per meter is `3.14X10^(-2)T`. The current flowing through the solenoid isA. 2AB. 3AC. 4AD. 5A |
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Answer» Correct Answer - D `I=(B)/(mu_0n)=(3.14xx10^-2)/(4pixx10^-7xx5000)=5A` |
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