InterviewSolution
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InterviewSolution
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The string fixed at both ends has standing wave nodes for which distance between adjacent nodes is `x_1`. The same string has another standing wave nodes for which distance between adjacent nodes is `x_2`. If `l` is the length of the string then `x_2//x_1=l(l+2x_1)`. What is the difference in numbers of the loops in the two cases?A. `1`B. `2`C. `3`D. `4` |
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Answer» Correct Answer - B Let no. of loops formed in first case `=n` `x_1n=l` .(i) Let no. of loops formed in second case `=(n+k)` `x_2(n+k)l` .(ii) From (i) and (ii) `x_2[(l)/(x_1)+k]=l,(x_2)/(x_1)=(l)/(l+kx_1)` Comparing with `(x_2)/(x_1)=(l)/(l+2x_1),k=2` |
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