The sum of `(1^(2)-1+1) (1!)+(2^(2)-2+1)(2!) +...+ (n^(2)-n+1) (n!)` is -A. `(n+2)!`B. `(n-1)((n+1)!)+1`C. `(n+2)!-1`D. `n((n+1)!)-1`

The sum of `(1^(2)-1+1) (1!)+(2^(2)-2+1)(2!) +...+ (n^(2)-n+1) (n!)` i

1.	The sum of `(1^(2)-1+1) (1!)+(2^(2)-2+1)(2!) +...+ (n^(2)-n+1) (n!)` is -A. `(n+2)!`B. `(n-1)((n+1)!)+1`C. `(n+2)!-1`D. `n((n+1)!)-1`
Answer» Correct Answer - B `T_(n)=(n^(2)-n+1)n!` `=(n^(2)-1)n!-(n-2)n!` `T_(n)=(n-1)(n+1)!-(n-1)n!` Sum `=1+(n-1) (n+1) !`

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The sum of `(1^(2)-1+1) (1!)+(2^(2)-2+1)(2!) +...+ (n^(2)-n+1) (n!)` is -A. `(n+2)!`B. `(n-1)((n+1)!)+1`C. `(n+2)!-1`D. `n((n+1)!)-1`

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