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The sum of 3 numbers are 10/3 : 21/5 : 49/8 is 4917. Find the numbers.... |
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Answer» io of the numbers is10/3 : 21/5 : 49/8Let, X be the common multiple.Then the numbers are10x/3, 21x/5 and 49x/8Given that :10x/3 + 21x/5 + 49x/8 = 4917or, (10/3 + 21/5 + 49/8)x = 4917or, 1639x/120 = 4917or, 1639x = 4917×120or, x = (4917×120)/1639or, x = 3×120 [SINCE 4917=3×1639]So, x = 360Therefore, the numbers are1200, 1512 and 2205. OK dear follow me ✌️ samile ✌ |
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