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The sum of ( 6a + 4b - c + 3 ) , ( 2b - 3c + 4 ) , ( 11b - 7a + 2c - 1 ) and ( 2c - 5a - 6 ) is (a) ( 4a - 6b + 2 ) (b) ( - 3a + 14b - 3c + 2 ) (c) ( - 6a + 17b ) (d) ( -6a + 6b + c - 4 ) |
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Answer» -step EXPLANATION:The sum of ( 6a + 4b - C + 3 ) , ( 2b - 3c + 4 ) , ( 11B - 7a + 2c - 1 ) and ( 2c - 5a - 6 ) is (c) ( - 6a + 17b ) |
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