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The sum of all real values of X satisfying the equation `(x^2-5x+5)^(x^2 + 4x -60) = 1` is:A. 6B. 5C. 3D. `-4` |
Answer» Correct Answer - C `(x^(2)-5x+5)^(x^(2)+4x-60)=1` Case I `x^(2)-5x+5=1` and `x^(2)+4x-60` can be any real number `impliesx=1,4` Case II `x^(2)-5x+c=-1` and `x^(2)+4x-60` has to be an even number ltbr gt`impliesx=2,3` For `x=2,3` For `x=3, x^(2)+4x-60` is odd `:.!=3` Hence `x=2` Case III `x^(2)-5x+5` can be any real number and `x^(2)+4x-60=0` `impliesx=-10,6` `implies` Sum of all values o `x=1+4+2-10+6=3` |
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