1.

The sum of first 47 terms of the series1/4+1/5-1/6-1/4-1/5+1/6+1/4+1/5-1/6.....is​

Answer»

-STEP EXPLANATION:a = 1/4d = 1/5- 1/4 = 1/20n = 47Sn = n/2(2A + ( n-1)d) = 47/2 × (1/2 + 23/10) = 47/2(28/10) = 329/5



Discussion

No Comment Found

Related InterviewSolutions