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The sum of first 47 terms of the series1/4+1/5-1/6-1/4-1/5+1/6+1/4+1/5-1/6.....is |
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Answer» -STEP EXPLANATION:a = 1/4d = 1/5- 1/4 = 1/20n = 47Sn = n/2(2A + ( n-1)d) = 47/2 × (1/2 + 23/10) = 47/2(28/10) = 329/5 |
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