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InterviewSolution
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The Sum Of Five Consecutive Even Numbers Of Set X Is 440. Find The Sum Of A Different Set Of Five Consecutive Integers Whose Second Least Number Is 121 Less Than Double The Least Number Of Set X ? |
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Answer» Let the five consecutive even numbers be 2(x - 2), 2(x - 1), 2X, 2(x + 1) and 2(x + 2) Their sum = 10X = 440 x = 44 => 2(x - 2) = 84 Second least number of the other set = 2(84) - 121 = 47 This set has its least number as 46. Sum of the numbers of this set = 46 + 47 + 48 + 49 + 50 = 48 - 2 + 48 - 1 + 48 + 48 + 1 + 48 + 2 => 5(48) = 240 Let the five consecutive even numbers be 2(x - 2), 2(x - 1), 2x, 2(x + 1) and 2(x + 2) Their sum = 10x = 440 x = 44 => 2(x - 2) = 84 Second least number of the other set = 2(84) - 121 = 47 This set has its least number as 46. Sum of the numbers of this set = 46 + 47 + 48 + 49 + 50 = 48 - 2 + 48 - 1 + 48 + 48 + 1 + 48 + 2 => 5(48) = 240 |
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