InterviewSolution
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InterviewSolution
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The sum of `n` terms of series `ab+(a+1)(b+1)+(a+2)(b+2)+…+(a+(n-1)(b+(n-1))` if `ab=(1)/(6)` and `(1+b)=(1)/(3)` isA. `(n)/(6)(1-2n)^(2)`B. `(n)/(6)(1+n-2n^(2))`C. `(n)/(6)(1-2n+2n^(2))`D. None of these |
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Answer» Correct Answer - C `(c )` `S=ab+[ab+(a+b)+1]+[ab+2(a+b)+2^(2)]+…+[ab+(n-1)(a+b)+(n-1)^(2)]` `=nab+(a+b)sum_(r=1)^(n-1)r+sum_(r=1)^(n-1)r^(2)` `=nab+(a+b)(n(n-1))/(2)+((n-1)(n)(2n-1))/(6)` `=(n)/(6)[1+(n-1){1+2n-1}]` `=(n)/(6)[1+2n(n-1)]=(n)/(6)(1-2n+2n^(2))` |
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