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the sum of present ages of 3 friends is 90 years if before 10 years their ages were in the ratio of 1:2:3 find their ages |
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Answer» Step-by-step explanation:LET their AGES 10 years ago is x, 2x and 3X years. 10 + 2x + 10 + 3x + 10 = 90 HENCE x= 10 B’s present age = (2x + 10) =30 years |
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