The sum of the digit of the two digit number is 9. when the digits are

1.	The sum of the digit of the two digit number is 9. when the digits are reversed the difference of the number is?
Answer» Answer: Let the TEN’s DIGIT be x and the unit’s digit be y. So the NUMBER formed is 10x+y Given x+y=9 Reversed number=10y+x Given, 10y+x=9+10x+y 9y=9+9x y=1+x Putting this in EQUATION 1, we get x+1+x=9 2x=8 x=4 y=9–4=5 So the number is 45

The sum of the digit of the two digit number is 9. when the digits are reversed the difference of the number is?

Answer»

Answer:

Let the TEN’s DIGIT be x and the unit’s digit be y.

So the NUMBER formed is 10x+y

Given x+y=9

Reversed number=10y+x

Given, 10y+x=9+10x+y

9y=9+9x

y=1+x

Putting this in EQUATION 1, we get

x+1+x=9

2x=8

x=4

y=9–4=5

So the number is 45

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The sum of the digit of the two digit number is 9. when the digits are reversed the difference of the number is?

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