The sum of the digits of a 2-digit no is 10. The no. Obtained by inter

1.	The sum of the digits of a 2-digit no is 10. The no. Obtained by interchanging the digits exceeds the original no. By 36. Find the original no
Answer» Let the number be xy , where X is the digit at 10's place and y is the digit at unit's place. Given, x+y=10 --------------------- ( 1 ) Original value = 10x+y After interchanging the digits the NEW number is yx and it's value is 10y+x . Given , 10y+x = 10x+y + 36 ----------------- ( 2 ) => 9y = 9x + 36 => y = x + 4 -------------------------- ( 3 ) From (1) and (3) , x+x+4=10 => x=3 and y= 7 Therefore, the original number is 37.

The sum of the digits of a 2-digit no is 10. The no. Obtained by interchanging the digits exceeds the original no. By 36. Find the original no

Answer»

Let the number be xy , where X is the digit at 10's place and y is the digit at unit's place.

Given, x+y=10 --------------------- ( 1 )

Original value = 10x+y

After interchanging the digits the NEW number is yx and it's value is 10y+x .

Given , 10y+x = 10x+y + 36 ----------------- ( 2 )

=> 9y = 9x + 36

=> y = x + 4 -------------------------- ( 3 )

From (1) and (3) ,

x+x+4=10 => x=3 and y= 7

Therefore, the original number is 37.