The sum of the digits of a two-digit number is 15. On subtracting 27 f

1.	The sum of the digits of a two-digit number is 15. On subtracting 27 from the given number its digits get reversed. Find the given number.
Answer» $\large\bf\underline {To \: find:-}$ We need to find the number. $\huge\bf\underline{Solution:-}$ $\bf\underline{\red{Given:-}}$ ● Sum of DIGITS = 15 ● if we subtract 27 from the original number then the digits gets reversed. Let :- Units place DIGIT be x and ten's place digit be y. Number formed = 10x + y ➳ Sum of digits = 15 ➳ x + y = 15 ➳ x = 15 - y ......1) ☘️According to Question :- On subtracting 27 from the given number its digits get reversed. ➛ (10x + y) - 27 = 10y + x ➛ 10x - x - 10y + y = 27 ➛ 9x - 9Y = 27 ▶Dividing both sides by 9 we get, ➛ x - y = 3 ⪼ From equation 1) ➛ 15 - y - y = 3 ➛ 15 - 2y = 3 ➛ - 2y = 3 - 15 ➛ - 2y = -12 ➛ y = 12/2 ➛ y = 6 ▶ putting VALUE of y = 6 in Equation 1) ➻ x = 15 - y ➻ x = 15 - 6 ➻ x = 9 ✝️ Original number :- 10x + y 10 × 9 + 6 90 + 6 96 Hence, ༒ Original Number is 96 ━━━━━━━━━━━━━━━━━━━━━━━━━

The sum of the digits of a two-digit number is 15. On subtracting 27 from the given number its digits get reversed. Find the given number.

Answer»

$\large\bf\underline {To \: find:-}$

$\huge\bf\underline{Solution:-}$

$\bf\underline{\red{Given:-}}$

Units place DIGIT be x and ten's place digit be y.

➳ Sum of digits = 15

➳ x + y = 15

➳ x = 15 - y ......1)

On subtracting 27 from the given number its digits get reversed.

➛ (10x + y) - 27 = 10y + x

➛ 10x - x - 10y + y = 27

➛ 9x - 9Y = 27

▶Dividing both sides by 9 we get,

➛ x - y = 3

⪼ From equation 1)

➛ 15 - y - y = 3

➛ 15 - 2y = 3

➛ - 2y = 3 - 15

➛ - 2y = -12

➛ y = 12/2

➛ y = 6

▶ putting VALUE of y = 6 in Equation 1)

➻ x = 15 - y

➻ x = 15 - 6

➻ x = 9

Hence,

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