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The sum of the digits of a two digit number is 7 the number obtained by interchanging the digits exceed the original number by 27. find the no. |
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Answer» Let the UNIT place be x Then, tens digit = 7 - x original number = 10 ( 7 - x ) + x = 70 - 10X + x = 70 - 9x After interchanging of the digits, the resulting two digit number will be 10x + 7 - x = 9x + 7According to the question, 9x + 7 = 70 - 9x + 27or, 9x + 9x = 97 - 7 or, 18x = 90 or, x = 90/18 x = 5 so, original number = 70 - 9x = 70 - 9 × 5 = 70 - 45 = 15 |
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