1.

The sum of the digits of a two digit number is 9. Also nine times this number is twice the number obtained by reversing the order of the digits find the number.​

Answer»

-step explanation:LET the ten's digit no. be X and one's digit no. be y.So the no. will be = 10x+y.Given : x+y=9-----(I) 9(10x+y)=2(10y+x) ⇒88x−11y=0 -----(II)On SOLVING I and II simultaneously you will get x=1 and y=8.Therefore your desired no. is 18.



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